Gamma ray colliding with an electron

AI Thread Summary
A gamma ray beam with an energy of 1.00 MeV collides with gold particles, resulting in reflected gamma rays with an energy of 0.2035 MeV. The discussion centers on applying Compton scattering to explain this energy change, emphasizing the need to consider the mass of an electron rather than that of a gold nucleus. Participants highlight the importance of correctly calculating the change in wavelength (Δλ) rather than simply subtracting the energies. After several attempts, one user successfully resolves the problem using the Compton scattering formula with a reflection angle of 180 degrees. This illustrates the consistency of the results with the theoretical model of gamma rays interacting with an isolated electron at rest.
lcd123
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Homework Statement


A beam of gamma rays of energy 1.00 MeV are aimed at a set of freely moving gold particles. The gamma rays reflected back have an energy of 0.2035 MeV. How is this result consistent with the model of a gamma ray reflecting from an isolated electron initially at rest?


Homework Equations


E^2-P^2c^2=m^2c^4



The Attempt at a Solution


I've tried a few ways using Compton scattering but to no avail.
Determining the momentum of the gamma ray.
 
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lcd123 said:

Homework Statement


A beam of gamma rays of energy 1.00 MeV are aimed at a set of freely moving gold particles. The gamma rays reflected back have an energy of 0.2035 MeV. How is this result consistent with the model of a gamma ray reflecting from an isolated electron initially at rest?

Homework Equations


E^2-P^2c^2=m^2c^4

The Attempt at a Solution


I've tried a few ways using Compton scattering but to no avail.
Determining the momentum of the gamma ray.
Welcome to Physics Forums.

Can you show your work on the Compton scattering calculation? For me, it worked out. Make sure that you:

1. Don't just subtract the two given energies, and use that to determine Δλ.
2. Do use the mass of an electron, not a gold nucleus or atom.
 
Thank you for your reply. After a few more tries I was able to solve it using Compton scattering with a reflection of 180.

:)
 
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