Gas Pressure at 25°C: 0.45 mol, 0.65 L

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The discussion focuses on calculating the pressure exerted by 0.450 mol of gas at 25°C in a 0.65 L vessel. The initial calculation using the ideal gas law resulted in a pressure of approximately 1714.4 kPa. While the calculation was correct, it was suggested that the equation could be rearranged for simplicity. The alternative formulation, P = nRT/V, streamlines the process for finding pressure. Overall, the participants agree on the accuracy of the result while discussing a more efficient method.
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what pressure will be exerted by 0.450 mol of a gas at 25 degrees Celsius if it is contained in a vessel wwhose volume is 0.65 L?

\frac{P_1 * 0.65 L}{298 K * 0.450 mol}=8.31_\frac{L*kPa}{K*mol}<br />

P_1 \sim 1714.4 kPa

is this right?
thanks
 
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Yes that is correct although you didn't setup the equation as best you could.

\frac{{PV}}<br /> {{RT}} = n

could have been changed to

\frac{{nRT}}<br /> {V} = P

to make it a much simpler calculation since you are actually looking for P
 
thanks pengwuino, you i know, the simple algebra doesn't bother me tho :)
 
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