Calculating the Mass of the Galactic Center with Kepler's Third Law

AI Thread Summary
The discussion centers on calculating the mass of the Galaxy using Kepler's Third Law, given the Sun's orbital speed of 220 km/sec and its distance of 8500 parsecs from the Galactic center. The gravitational force acting on the Sun is equated to the centrifugal force due to its orbit, leading to the formula GMm/r^2 = mV^2/r, which allows for the calculation of the Galaxy's mass (M) through substitution. There is some confusion regarding the application of Kepler's Third Law, as it traditionally relates to the periods and distances of planetary orbits rather than mass calculations. Despite this, the original poster seeks clarification and assistance in solving the problem as assigned by their Astronomy professor. The conversation highlights the intersection of gravitational physics and classical mechanics in understanding galactic dynamics.
Morpheus
I'm not good at this stuff, so I need some help from some smarter people...:smile:

The speed of the Sun in its orbit about the Galactic center is 220 km/sec. Its distance from the center is 8500 pc. Assuming that the Sun's orbit is circular, calculate the mass of the Galaxy (in solar masses) interior to the Sun's orbit from Kepler's Third Law. Recall that the circumference of a circle is 2 pi r, where r is the radius. Remember that 1 pc is 206265 AU and 1 AU is 1.5x10^8 km.

Any help would be greatly appreciated!
 
Physics news on Phys.org
...

Assuming that the mass of the galaxy is concentrated at its center, the force of the galaxy of mass M on the sun of mass m separated by a distance r from the galaxy center is:

F = GMm/r^2. This force will be equal to the centrifugal force due the revolution of the sun around the galaxy.
Thus,

GMm/r^2 = mV^2/r, where, V is the velocity of sun around the galaxy.

From this u can calculate the value of M - the mass of the galaxy (Its, just mere substitution...)


Sridhar
 
sridhar_n's response is exactly what you need but I am puzzled about the reference to "Kepler's third law".

Kepler's third law is: The ratio of the squares of the revolutionary periods for two planets is equal to the ratio of the cubes of their semimajor axes.

Of course one can extend this to stars orbiting the galaxy but this says nothing about mass. Kepler's laws were purely descriptive. Kepler knew nothing about gravitational force or how mass affected orbital period.
 
Thanks for the help. All I know is my Astronomy professor asked us this question and told us to refer to Kepler's Third Law.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
I was thinking using 2 purple mattress samples, and taping them together, I do want other ideas though, the main guidelines are; Must have a volume LESS than 1600 cubic centimeters, and CAN'T exceed 25 cm in ANY direction. Must be LESS than 1 kg. NO parachutes. NO glue or Tape can touch the egg. MUST be able to take egg out in less than 1 minute. Grade A large eggs will be used.
Back
Top