Gauss's Law Electricity: Electric Field Between 2 Sheets

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SUMMARY

The electric field between two square metal plates is calculated to be 180 N/C, with each plate measuring 1.0 m on a side and separated by 3.0 cm. The charge density is determined using the formula charge density = charge / (area x Eo), resulting in a charge density of 3.186e-9 C/m². Consequently, the charge on each plate is calculated to be 3.186e-9 C. The distance between the plates does not affect the charge calculation in this scenario.

PREREQUISITES
  • Understanding of Gauss's Law
  • Familiarity with electric fields and charge density
  • Knowledge of the permittivity of free space (Eo = 8.85e-12 F/m)
  • Basic algebra for solving equations
NEXT STEPS
  • Study Gauss's Law applications in electrostatics
  • Learn about the concept of electric field strength and its calculations
  • Explore the relationship between charge density and electric field
  • Investigate edge effects in electric fields for real-world applications
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Physics students, electrical engineers, and anyone studying electrostatics or electric fields in conductive materials.

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Homework Statement


The electric field between two square metal plates is 180 N/C. The plates are 1.0 m on a side and are separated by 3.0 cm, as in the figure. What is the charge on each plate? Neglect edge effects.
22-29.gif


Homework Equations


i don't know how to make any fancy sybols sorry

charge density = charge / (area x Eo)

electric field = charge density / 2

The Attempt at a Solution



180 = charge density/(2 x 8.85e-12)
charge density = 3.186e-9

3.186e-9 = Q / 1
Q = 3.186e-9

I know that the distance between the two sheets has to be taken into consideration, but I'm not sure where.
 
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never mind, i figured it out. distance doesn't matter at all.

[STRIKE]180[/STRIKE] 90 = charge density/(2 x 8.85e-12)
charge density = [STRIKE]3.186e-9[/STRIKE] 1.593e-9

[STRIKE]3.186e-9[/STRIKE] 1.593e-9 = Q / 1
Q = [STRIKE]3.186e-9[/STRIKE] 1.593e-9
 

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