# Gauss's Law Electricity: Electric Field Between 2 Sheets

1. Sep 25, 2009

### ryanmcf10

1. The problem statement, all variables and given/known data
The electric field between two square metal plates is 180 N/C. The plates are 1.0 m on a side and are separated by 3.0 cm, as in the figure. What is the charge on each plate? Neglect edge effects.

2. Relevant equations
i don't know how to make any fancy sybols sorry

charge density = charge / (area x Eo)

electric field = charge density / 2
3. The attempt at a solution

180 = charge density/(2 x 8.85e-12)
charge density = 3.186e-9

3.186e-9 = Q / 1
Q = 3.186e-9

I know that the distance between the two sheets has to be taken into consideration, but I'm not sure where.

2. Sep 25, 2009

### ryanmcf10

never mind, i figured it out. distance doesn't matter at all.

[STRIKE]180[/STRIKE] 90 = charge density/(2 x 8.85e-12)
charge density = [STRIKE]3.186e-9[/STRIKE] 1.593e-9

[STRIKE]3.186e-9[/STRIKE] 1.593e-9 = Q / 1
Q = [STRIKE]3.186e-9[/STRIKE] 1.593e-9