Calculating Charge Density and Total Charge Using Gauss's Law

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The electric field in the given problem is expressed as E = kr^3 in spherical coordinates. To find the charge density, the divergence of the electric field is calculated, resulting in ρ = 5kε₀r². For the total charge within a sphere of radius R, two methods yield the same result: integrating the charge density over the sphere's volume gives Q = 4πε₀R⁵, and applying Gauss's law confirms this by using the surface integral of the electric field. The calculations and approaches for both parts are verified as correct. The discussion emphasizes the consistency of results obtained through different methods in electrostatics.
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Homework Statement



Suppose the electric field in some region is found to be \vec{E} = kr^{3} \hat{r}, in spherical coordinates (k is some constant).

(a) Find the charge density ρ.

(b) Find the total charge contained in a sphere of radius R, centered at the origin. (Do it two different ways.)

Homework Equations



The Attempt at a Solution



(a) Use the formula for the divergence of a vector in spherical basis to get \nabla . \vec{E} = 5kr^{2} so that \rho = 5k\epsilon_{0}r^{2}.

(b) Q is the volume integral of \rho over the volume of the sphere. So, we integrate over d\phi, integrate sinθ over dθ, integrate the \rho times r^{2} over dr and multiply the three results. The process gives us 4\pi \epsilon_{0} R^{5}.

Q can also be found using the integral form of Gauss's law, where the surface integral of the electric field is taken with the infinitesimal area, which is R2 sinθ dθ d∅ r, where r is the unit vector in the radial direction. We take the constants out of the integral and integrate 1 over phi and sinθ over theta to obtain the same Q as above.

Please could you check if the process and the answers are correct?
 
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a) Looks good to me. I get the same.
b) Is it a hollow spherical shell. Then you can use that the electric field is constant over the surface(fixed r) and only multiply by the area of the sphere(shell) because:
\oint \vec{E}\cdot\vec{da} = \oint E\,\text{d}a = E\oint 1\text{d}a = E 4\pi R^2 = Q/\epsilon_0 \Leftrightarrow Q = 4\pi \epsilon_0 kR^5
The dot product \vec{E}\cdot\vec{da} is just da times E cause they point in the same direction.
 
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