Geometry (calculating degrees,minutes)

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this might be a simple question
but i do not know how to convert degrees to degrees,minutes
say if i have
74.39 degrees it converts to 74 degrees 24 minutes
i do know that
1 minute = 1/60 degrees... please help
 
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74.39 deg = 74 deg + 0.39 deg

0.39 deg = 0.39 deg * 60 min/deg = 23.4 min = 23 min + 0.4 min

0.4 min = 0.4 min * 60sec/min = 24 sec

So, 74.39 deg = 74 deg 23 min 24 sec

PS : This would go in Precalc Math.
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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