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Get in terms of d

  1. Feb 24, 2006 #1
    I dont know why I cant do this, all I need to do is to get the variable d on one side and everything else on the other side:

    constants: the f's and s
    variables: l and d




    when I try to solve for d, i get d^2(...)+d(....)=constants
    I cant solve this because both sides will have a d in it, is there something I'm missing?
    Last edited: Feb 24, 2006
  2. jcsd
  3. Feb 24, 2006 #2


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    What kind of equation is d^2(...)+d(....)=constants?

    I bet you know how to solve (...) x^2 + (...) x + (...) = 0.
  4. Feb 24, 2006 #3
    yes but the (...) has the variable l in it (l is not a constant), so I cant solve for d. I need to solve for d in terms of l
  5. Feb 24, 2006 #4


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    So? How does that change anything?
  6. Feb 24, 2006 #5


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    What matters is that l is not a function of d.

    What I'm saying is, if x and t are two independant variables, and we have


    then the solutions for x are a function of t:

    [tex]x_{1,2}(t) = \frac{-g(t) \pm \sqrt{g^2(t) - 4f(t)h(t)}}{2f(t)}[/tex]
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