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A bead slides without friction around a loop-the-loop. The bead is released from height of 25.1m from the bottom of the loop-the-loop which has a radius of 9m. THe acceleration due to gravity is 9.8 m/s^2. There is a point A at the very top of the loop. I need to know the normal force(Fn) at that point if the mass is 3 g. I converted the 3 g to kg and then tried to solve. I set Fn-mg=0 so Fn=mg. So I took 0.003 and multiplied by 9.8m/s^2 but got the answer wrong.