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Gibb's phase rule and counting phases

  1. Dec 16, 2013 #1

    I was wondering, suppose I had a mixture of a few liquids that were immiscible, say 4.

    Now, when calculating the degrees of freedom, I am confused about the number of phases.

    I think the number of components is 4, but the number of phases should be 1, liquid, right? Or does each component in the liquid phase count as one phase. I have seen problems that seem contradictory to what I think the answer should be

    F = C - P + 2

    F = 4 - 1 + 2 = 5
  2. jcsd
  3. Dec 17, 2013 #2


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    Four mutually immiscible liquids? Four liquid phases.
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