Given tension and acceleration determine max weight

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Homework Help Overview

The problem involves determining the maximum weight of a fish that can be landed using a fishing line with a specified tension while accelerating the fish upward. The context includes concepts from dynamics and forces, specifically relating to tension, weight, and acceleration.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the forces acting on the fish, including tension and gravitational force. There are attempts to express the forces mathematically and to set up equations based on the given parameters.

Discussion Status

The discussion has progressed through various attempts to formulate the problem mathematically. Some participants have provided guidance on expressing the forces in terms of mass and gravity. There is recognition of the complexity introduced by having multiple unknowns, and some participants are exploring how to manipulate the equations to isolate variables.

Contextual Notes

Participants note the constraints of the problem, including the maximum tension of the fishing line and the acceleration of the fish. There is an acknowledgment of the need to express everything in terms of mass and the gravitational force acting on the fish.

jsewell
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Homework Statement


A fisherman in a boat is using a "10- test" fishing line. This means that the line can exert a force of 45 without breaking (1lb = 4.45N). If he accelerates the fish upward at 1.8m/s/s , what maximum weight fish can he land, in Newtons?


Homework Equations



F=ma

The Attempt at a Solution



Failed Answers : 25, 6

FBD demostrates a line from a fishes mouth. Gravity points down, Force of pull goes up, acceleration is upwards at 1.8m/s/s. I've tried setting the sum of all the forces in the y direction to 45N and then solving for m. That only gave me 25kg, don't know what I was thinking there. Then I tried using F=ma countless times to no avail.
 
Last edited:
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jsewell said:
FBD demostrates a line from a fishes mouth. Gravity points down, Force of pull goes up, acceleration is upwards at 1.8m/s/s.
Good. Express that mathematically.
I've tried setting the sum of all the forces in the y direction to 45N and then solving for m.
45 N is the maximum force of pull (tension in the line), not the net force.
 
Soo...(Force on line - Force of gravity) = mass(1.8m/s/s)

where the we set the Force on the line to 45 Newtons. The heaviest fish you can pull out of the water at that rate will still be acomplished at 45 Newtons of Tension. The question goes on about how many Newtons gravity will be playing at, the weight of the fish. So...

Force of gravity = -[mass(1.8 m/s/s) - force on line]

mg = -ma + 45

mg = -m(1.8m/s/s) + 45

My problem with this is that I have two unknowns (Force of Gravity and Mass) so this equation has me stuck...
 
Last edited:
jsewell said:
My problem with this is that I have two unknowns (Force of Gravity and Mass) so this equation has me stuck...
They are related. Given a mass, what's the weight? Express everything in terms of mass.
 
well weight is equal to mg. An objects mass in kg and the factor of gravity (9.8 N/kg).

I'll assume my equation was sound and all your asking is to put in terms of mass. This should yeild me...

mg = -m(1.8N/kg) + 45

Idk what you mean friend. I got to thinking and figured that I can determine the objects mass when the line is fully loaded and not accelerating. That figure, 4.6kg would is only useful if the object is stationary or already at a constant velocity. I am lost here
 
jsewell said:
well weight is equal to mg. An objects mass in kg and the factor of gravity (9.8 N/kg).

I'll assume my equation was sound and all your asking is to put in terms of mass. This should yeild me...

mg = -m(1.8N/kg) + 45
Excellent. Now just solve for the mass.

Idk what you mean friend. I got to thinking and figured that I can determine the objects mass when the line is fully loaded and not accelerating. That figure, 4.6kg would is only useful if the object is stationary or already at a constant velocity. I am lost here
Just solve the equation above for the mass. (And then find the weight of the mass, since that's what the question asks for.) That equation will tell you the most mass of fish you can accelerate, since 45 N is the most force you can exert on the line without breaking it.
 
so after some algebraic manipulation I can solve for m

m = 45N
---------
g + 1.8N/kg

setting "g" to 9.8N/kg yeilds

m = 3.88kg

So the weight is 3.88kg x 9.8N/kg

38 Newtons!
 
Answer was correct. Sometimes all you need is a person to tell you your on the right track.

Thanks Doc Al
 

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