Given tension and acceleration determine max weight

In summary,The fisherman in a boat is using a 10-test fishing line. This means that the line can exert a force of 45 without breaking (1lb = 4.45N). If he accelerates the fish upward at 1.8m/s/s , he can land the heaviest fish possible.
  • #1
jsewell
10
0

Homework Statement


A fisherman in a boat is using a "10- test" fishing line. This means that the line can exert a force of 45 without breaking (1lb = 4.45N). If he accelerates the fish upward at 1.8m/s/s , what maximum weight fish can he land, in Newtons?


Homework Equations



F=ma

The Attempt at a Solution



Failed Answers : 25, 6

FBD demostrates a line from a fishes mouth. Gravity points down, Force of pull goes up, acceleration is upwards at 1.8m/s/s. I've tried setting the sum of all the forces in the y direction to 45N and then solving for m. That only gave me 25kg, don't know what I was thinking there. Then I tried using F=ma countless times to no avail.
 
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  • #2
jsewell said:
FBD demostrates a line from a fishes mouth. Gravity points down, Force of pull goes up, acceleration is upwards at 1.8m/s/s.
Good. Express that mathematically.
I've tried setting the sum of all the forces in the y direction to 45N and then solving for m.
45 N is the maximum force of pull (tension in the line), not the net force.
 
  • #3
Soo...(Force on line - Force of gravity) = mass(1.8m/s/s)

where the we set the Force on the line to 45 Newtons. The heaviest fish you can pull out of the water at that rate will still be acomplished at 45 Newtons of Tension. The question goes on about how many Newtons gravity will be playing at, the weight of the fish. So...

Force of gravity = -[mass(1.8 m/s/s) - force on line]

mg = -ma + 45

mg = -m(1.8m/s/s) + 45

My problem with this is that I have two unknowns (Force of Gravity and Mass) so this equation has me stuck...
 
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  • #4
jsewell said:
My problem with this is that I have two unknowns (Force of Gravity and Mass) so this equation has me stuck...
They are related. Given a mass, what's the weight? Express everything in terms of mass.
 
  • #5
well weight is equal to mg. An objects mass in kg and the factor of gravity (9.8 N/kg).

I'll assume my equation was sound and all your asking is to put in terms of mass. This should yeild me...

mg = -m(1.8N/kg) + 45

Idk what you mean friend. I got to thinking and figured that I can determine the objects mass when the line is fully loaded and not accelerating. That figure, 4.6kg would is only useful if the object is stationary or already at a constant velocity. I am lost here
 
  • #6
jsewell said:
well weight is equal to mg. An objects mass in kg and the factor of gravity (9.8 N/kg).

I'll assume my equation was sound and all your asking is to put in terms of mass. This should yeild me...

mg = -m(1.8N/kg) + 45
Excellent. Now just solve for the mass.

Idk what you mean friend. I got to thinking and figured that I can determine the objects mass when the line is fully loaded and not accelerating. That figure, 4.6kg would is only useful if the object is stationary or already at a constant velocity. I am lost here
Just solve the equation above for the mass. (And then find the weight of the mass, since that's what the question asks for.) That equation will tell you the most mass of fish you can accelerate, since 45 N is the most force you can exert on the line without breaking it.
 
  • #7
so after some algebraic manipulation I can solve for m

m = 45N
---------
g + 1.8N/kg

setting "g" to 9.8N/kg yeilds

m = 3.88kg

So the weight is 3.88kg x 9.8N/kg

38 Newtons!
 
  • #8
Answer was correct. Sometimes all you need is a person to tell you your on the right track.

Thanks Doc Al
 

1. What is the formula for calculating maximum weight given tension and acceleration?

The formula for calculating maximum weight (W) given tension (T) and acceleration (a) is W = T / a, where T is in newtons (N) and a is in meters per second squared (m/s^2).

2. How do I determine the maximum weight if I only have the tension and acceleration values?

To determine the maximum weight, simply plug the given values for tension and acceleration into the formula W = T / a. This will give you the maximum weight in newtons (N).

3. Can the maximum weight be negative?

No, the maximum weight cannot be negative. It is a measure of the maximum force that an object can withstand before breaking or failing.

4. Is the maximum weight affected by the object's mass?

Yes, the maximum weight is affected by the object's mass. A heavier object will have a higher maximum weight than a lighter object, assuming the tension and acceleration values remain the same.

5. How can I use this equation in real-life applications?

This equation can be used in various real-life applications, such as determining the maximum weight a bridge can support based on the tension and acceleration caused by traffic, or calculating the maximum weight a cable can hold before breaking. It is also commonly used in engineering and construction to ensure the safety and stability of structures and equipment.

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