Gold Electrodes and Capacitance

AI Thread Summary
Immersing gold electrodes in a saline solution under a fixed voltage increases capacitance due to the saline acting as a dielectric, which enhances charge storage. The discussion highlights that the saline's higher relative dielectric constant compared to air contributes to this increase. Regarding current, the fixed voltage suggests that current should remain unchanged; however, the presence of saline introduces complexities related to electrolysis. The participants clarify that the electrolysis process alters charge dynamics at the electrodes, potentially impacting current flow. Overall, the interaction of voltage, capacitance, and saline is crucial in understanding the system's behavior.
OHMy..G.Simon?
Messages
2
Reaction score
0

Homework Statement


Well its 2 questions:
  1. Immersing a pair of gold electrodes in a saline solution in the presence of a fixed voltage causes the capacitance to:
    1. Increase
    2. Decrease
    3. Remain unaltered
    4. Increase briefly and then return to its original value
  2. Immersing a pair of gold electrodes in a saline solution in the presence of a fixed voltage causes the Current to: (same answers as above)

Homework Equations




The Attempt at a Solution


I have been racking my brain over this for the last several hours. It was supposed to be made clear in a practical class that ended up having faulty equipment, but i digress...

I basically began with the idea that the parallel plates would act as capacitors and when they were submerged in saline, it would act as the dielectric (higher relative dielectric than air). Given the fixed voltage, this would increase the charge that would be able to be stored by polarising the dielectric and reducing the electric field? (Am I at least on the right track here?) So i concluded that the capacitance would increase.

The second question is the one that is giving me real trouble. I can't find any association between capacitance and current and I definitely don't understand how immersing gold electrodes in saline would change the current. The only thing I could come up with is the fact that the voltage is again fixed and given that voltage is proportional to current, would it be correct to say that the current shouldn't change? Or does the saline affect this?

I was reading about how one electrode is - and the other is + and how the electrons are both being attracted by the protons and repelled by the potential voltage and so in a capacitor there is a point where there is no net charge movement because the forces are equal?? Again this was just something that kind of made sense.

At this point I'm thinking that current would remain unaltered.

Help would be much appreciated, Thanks
 
Physics news on Phys.org
Inserting electrodes with a voltage into a saline solution changes it into an electrolysis setup.
Since the voltage is kept fixed the question then becomes what happens to the charge at the electrodes.
 
Last edited:
Ahh okay that makes much more sense now. Thanks for the help.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top