- #1
- 668
- 68
If [tex]y=sin^3(1-2x)[/tex] then [tex]\frac{dy}{dx}=?[/tex]
a)[tex]3sin^2(1-2x)[/tex]
b)[tex]-2cos^3(1-2x)[/tex]
c)[tex]-6sin^2(1-2x)[/tex]
d)[tex]-6sin^2(1-2x)cos(1-2x)[/tex]
e)[tex]-6cos^2(1-2x)[/tex]
Here is my work:
[tex]\frac{dy}{dx}=3cos^2(1-2x)(-2)=-6cos^2(1-2x)[/tex]
When I checked the problem with my friend, he had (B) and after we discussed it we decided to graph the functions to find the answer and according to that the answer is (D). Can someone show me the work for that answer, I don't really understand how it could be obtained.
a)[tex]3sin^2(1-2x)[/tex]
b)[tex]-2cos^3(1-2x)[/tex]
c)[tex]-6sin^2(1-2x)[/tex]
d)[tex]-6sin^2(1-2x)cos(1-2x)[/tex]
e)[tex]-6cos^2(1-2x)[/tex]
Here is my work:
[tex]\frac{dy}{dx}=3cos^2(1-2x)(-2)=-6cos^2(1-2x)[/tex]
When I checked the problem with my friend, he had (B) and after we discussed it we decided to graph the functions to find the answer and according to that the answer is (D). Can someone show me the work for that answer, I don't really understand how it could be obtained.