Graphing the Derivative of y = x^4 + 2x^3 + x^2 + 6

  • Thread starter Thread starter courtrigrad
  • Start date Start date
  • Tags Tags
    Derivative Graph
AI Thread Summary
To graph the derivative of the function y = x^4 + 2x^3 + x^2 + 6, one must identify where the original function's slope is zero, as these points indicate where the derivative crosses the x-axis. The derivative will be positive when the function is increasing and negative when it is decreasing. Critical points, where the function changes from increasing to decreasing or vice versa, correspond to local maxima and minima of the derivative. Understanding the relationship between the function and its derivative is crucial, as the derivative represents the slope of the tangent line at any point on the function. Overall, graphing the derivative requires careful analysis of the original function's behavior rather than simply drawing horizontal lines.
courtrigrad
Messages
1,236
Reaction score
2
Hello all

Given the graph of the function y = x^4 + 2x^3 + x^2 + 6 graph its derivative.

In other words, how would you graph the derivative soley based on the function's graph? Would you just draw a horizontal line if the slope is 0, etc..?

Thanks
 
Physics news on Phys.org
courtrigrad said:
Hello all

Given the graph of the function y = x^4 + 2x^3 + x^2 + 6 graph its derivative.

In other words, how would you graph the derivative soley based on the function's graph? Would you just draw a horizontal line if the slope is 0, etc..?

Thanks


This is a weird question.From the graph of the function,of that function actually,u could tell where the derivative is zero and the signs it has on various intervals between its zeros.And nothing more...

Daniel.
 
courtrigrad said:
Hello all

Given the graph of the function y = x^4 + 2x^3 + x^2 + 6 graph its derivative.

In other words, how would you graph the derivative soley based on the function's graph? Would you just draw a horizontal line if the slope is 0, etc..?

Thanks
No. The points where the slope of the original function is zero are the points where the graph of your derivative crosses the x-axis. If the slope of the function is positive, your derivative is above the x-axis. If the slope of the function is negative, your derivative is below the line. If you can pick out the inflection points (where the curve changes shape), these are the points where your derivative hits a local maximum or minimum.

The function they give you can be a little tricky if you use a graphing calculator and don't look at it closely. You actually have two local minimums and a local maximum - these are the three points where your derivative crosses zero. Actually determining your critical points is always your best for graphing the derivative of the function.
 
Have I totaly missunderstud this. Can you really graph a derivate, or just a tangent or are they synonyms of each other in this context?
 
danne89 said:
Have I totaly missunderstud this. Can you really graph a derivate, or just a tangent or are they synonyms of each other in this context?

The velues of the derivative (seen as a function:"derivative (x)") are the values the slope of the original graph can take.
U can't really graph a derivative knowing the graph of the original function.

Daniel.
 
So, when you refere to the derivate you refere to the function and when you refere to the tangent you specificly means the line?
 
Yes,the derivative is the function and its "y" values (the values from its range/image) are the values for the slope of the function.And they correspond to the same domain:e.g."f" has the slope at the point (7,f(7)) f'(7) .

Daniel.
 
yes... and the slope of tangent is the value of derivative(of the function)...
 
danne89 said:
Have I totaly missunderstud this. Can you really graph a derivate, or just a tangent or are they synonyms of each other in this context?
Yes. A simple way to illustrate the difference.

Your velocity is the derivative of your position. Your instantaneous velocity gives the rate of change in your position at a given instant. Your velocity at that exact instant would be the equivalent of the slope of your tangent line.

But, how about if you drive at 60 kph for 30 minutes, stop at a stop light for 2 minutes, then turn onto the highway and drive 145 kph for an hour, get pulled over by the police and remain motionless for the 30 minutes it takes the policeman to write your ticket, then despondently drive 90 kph for the 45 minutes it takes to complete your trip.

The graph of your derivative is a lot more than just one tangent line. It includes all the different velocities you travelled, including all the velocities you passed through when accelerating from 60 to 0 to 145, etc.
 
Back
Top