Griffith Intro to QM, 1st order perturb theory in time-dep

Click For Summary
SUMMARY

The discussion centers on first-order perturbation theory in time-dependent quantum mechanics, specifically addressing the coefficients ca(t) and cb(t) derived from the Hamiltonian perturbation H'(t). The participants clarify that the condition ca^2 + cb^2 = 1 does not hold at first order, as the result yields |ca|^2 + |cb|^2 > 1. To resolve this discrepancy, one must either consider higher-order perturbation terms or adjust the coefficients to maintain the norm conservation, leading to |ca|^2 = 1 - |cb|^2.

PREREQUISITES
  • Understanding of first-order time-dependent perturbation theory (TDPT)
  • Familiarity with quantum mechanics concepts such as wave functions and probability amplitudes
  • Knowledge of Hamiltonian operators and their role in quantum systems
  • Basic calculus for evaluating integrals in quantum mechanics
NEXT STEPS
  • Study higher-order perturbation theory in quantum mechanics
  • Explore the implications of norm conservation in quantum state evolution
  • Learn about the mathematical formulation of time-dependent Hamiltonians
  • Investigate the role of complex coefficients in quantum probability amplitudes
USEFUL FOR

Students and researchers in quantum mechanics, particularly those focusing on perturbation theory and its applications in time-dependent systems.

tjsgkdms1111

Homework Statement


ca(0)=1, cb(0)=0
zeroth: ca(t)=1, cb(t)=0
1st: ca(t)=1, cb(t)=i/hbar*integral(H'(t) exp(iwt)) dt
ca^2+cb^2=1 to 1st order of H'.: What does it mean?
it is evidently not 1 at all.

Homework Equations

The Attempt at a Solution

 
Physics news on Phys.org
tjsgkdms1111 said:

Homework Statement


ca(0)=1, cb(0)=0
zeroth: ca(t)=1, cb(t)=0
1st: ca(t)=1, cb(t)=i/hbar*integral(H'(t) exp(iwt)) dt
ca^2+cb^2=1 to 1st order of H'.: What does it mean?
it is evidently not 1 at all.

Homework Equations

The Attempt at a Solution

Is this really a homework question, or you don't understand something about TDPT?

While your question is not clear, I get the feeling that you are bothered by the fact that ##|c_a|^2 + |c_b|^2 > 1##, but this is indeed the result you get from 1st-order TDPT. You have to go to higher order to resolve this, or take that by conservation of the norm ##c_a## must be modified such that ##|c_a|^2 = 1 - |c_b|^2 ## (but that only tells you the probability of staying gin the initial state, and not the actual complex coefficient ##c_a##).
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
Replies
8
Views
3K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K