Group theory, subgroup question

rallycar18
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Let A be a subgroup of G. If g \in G, prove that the set {g^{-1} ag ; a \in A} is also a subgroup of G.

Thanks for any help.
 
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What's the definition of a subgroup?
 
Mark44 said:
What's the definition of a subgroup?

Thanks, mark- i left that out.

A subset A of a group (G,*) is called a subgroup if the elements of A form a group under *.

* is the binary operation of the two groups.
 
You have two choices:
1) Either prove that the set is a group by confirming that it satisfies all the group axioms (there are only four, so that's not too bad)

2) Use a theorem that allows you to confirm something is a subgroup in fewer steps (I don't know if you know any)

Just focusing on 1, can you for example prove that the identity is contained in that set?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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