- #1
Antti
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A bar is guided so that one end moves on a vertical line and the other on a horizontal line. A spring is attached to the upper end according to the figure. Any friction is neglected.
http://web.comhem.se/~u48800174/springbar.jpg
I want to find out how x varies in time. If the center of mass would have been at x and k is the spring coefficient and m the mass, then
x = A sin (\sqrt{k/m}t + \phi_{0})
But now the center of mass is at the center of the rod (with length d) instead. More specifically:
\overline{CM} = (x/2, -\sqrt{d^2 - x^2}/2
How does this affect the equation of motion? Is it perhaps still the same? My intuition tells me something would change when the spring isn't attached at the COM but i don't know what and why. Thankful for help!
http://web.comhem.se/~u48800174/springbar.jpg
I want to find out how x varies in time. If the center of mass would have been at x and k is the spring coefficient and m the mass, then
x = A sin (\sqrt{k/m}t + \phi_{0})
But now the center of mass is at the center of the rod (with length d) instead. More specifically:
\overline{CM} = (x/2, -\sqrt{d^2 - x^2}/2
How does this affect the equation of motion? Is it perhaps still the same? My intuition tells me something would change when the spring isn't attached at the COM but i don't know what and why. Thankful for help!
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