ApplePion said:
"There are no other SM particles which could give this observation""
I don't know what "SM" means, but I doubt that matters.
The thing discovered decayed into 2 photons. A meson made of a quark and its own anti-quark, could decay into 2 photons--indeed the J/psi particle (made of a charmed quark and an anti-charm quark) decays into 2 photons. So how do we know that the new particle is not a combination of a very heavy newly encountered quark and its anti-partner?
SM=Standard Model
The SM contains three quark families. A forth family would be new physics and therefore beyond the SM. Apart from this:
- This quark would form other combinations, too. None of them was observed.
- It would have a mass of ~63 GeV, and therefore have been within the range of LEP (as the process e- e+ -> q anti-quark is quite likely, if the energy allows it) and Tevatron.
A high Higgs mass would have given some trouble.
However, at 126 GeV it is quite "boring" - if it is the Higgs, it is in the expected region.
About your second link:
The decay of a Higgs boson into a pair of W bosons h --> W^+W^-, is a dominant mode for Higgs boson masses above 135 GeV.
The discovered boson does not have a mass above 135 GeV. Below, the sensitivity of this channel is quite bad.
I don't know exactly why but the region around 120 GeV is often quoted as the most difficult mass region to find the Higgs
The decay channel b b-bar is dominant, and this has a lot of background. WW has the missing energy issue with neutrinos, gluon gluon is spammed by background, tau tau has the same neutrino issue again. The easier channels have a smaller branching fraction.
The observation is mainly based on the 2 photon channel now, with a branching fraction of a few permille.