Heat capacity of water -- experimental determination

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SUMMARY

The experimental determination of the heat capacity of water involves cooling water in a beaker to below freezing and measuring the time taken to reach various temperatures as it warms in a controlled environment. The equations used include Q=C ΔT, Q=L, and Q=P Δt, allowing for the calculation of heat capacities for both ice and liquid water. The experiment reveals that the heat transfer to ice raises its temperature until it reaches 0ºC, after which the temperature remains constant during the phase change. The results indicate that while absolute heat capacities cannot be determined, the ratios between the heat capacities of ice and water can be calculated.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically heat transfer.
  • Familiarity with the concepts of specific heat capacity and latent heat.
  • Knowledge of linear regression for data analysis.
  • Basic proficiency in using experimental measurement tools.
NEXT STEPS
  • Learn about the specific heat capacity of ice and water in detail.
  • Explore the concept of latent heat and its applications in phase changes.
  • Study linear regression techniques for analyzing experimental data.
  • Investigate the effects of temperature on the heat capacities of various substances.
USEFUL FOR

Students in physics or engineering, researchers in thermodynamics, and educators looking to enhance their understanding of heat transfer and phase changes in water.

sunquick
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Homework Statement


A quantity of water in a beaker of negligible thermal capacity is cooled to a few degrees below freezing point. The beaker is then placed in a warm room, and the times recorded at which it is at various temperatures as it gradually warms. The observations were:

temperature/ºC time/min:
-3.0 0
-2.0 0.93
-1.0 1.89
0 2.92
...
0 169.72
1.0 171.84
2.0 174.04
3.0 176.34

Homework Equations


Q=C \Delta T
Q= L
Q= P \Delta t

The Attempt at a Solution



My question concerns part b)
I assume the power delivered to the system is constant.
So Q=C \Delta T = P \Delta t or
\frac{\Delta t}{\Delta T} = C/P = const

So I fit a straight line to the experimental points to determine the slope and so to know C/P.
There will be two heat capacities, one for ice and the other for liquid water. I can determine the ratio o C_ice / C_water, and also of the latent heat necessary to melt the ice by noting that

P \frac{\Delta t_1}{\Delta T} = C
P \Delta t_2 = L
\Delta t_2 \frac{\Delta T}{\Delta t_1} = L / C

I can find the heat capacities and latent heats with respect to one another, but I can't seem to know how find one of them in "absolute terms". My question is if that is possible, and what other quantitative results can be obtained from the observations?
 
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Please state exactly what the question asks for.
 
Sorry I forgot tho type that part of the problem:

a) Explain the general form of the experimental results.
b) What quantitative results can you deduce from the observations?

For part a) I have to explain that heat is transferred to the ice, increasing its temperature, till it reaches 0ºC. Then it stays at that temperature until all the ice has melted away, because all the heat entering the system is going into changing the phase of the water instead of increasing its temperature. Once the ice has melted, the temperature rises again, this time at a different rate than before because water has a different specific heat capacity than ice.
 
sunquick said:
Sorry I forgot tho type that part of the problem:

a) Explain the general form of the experimental results.
b) What quantitative results can you deduce from the observations?

For part a) I have to explain that heat is transferred to the ice, increasing its temperature, till it reaches 0ºC. Then it stays at that temperature until all the ice has melted away, because all the heat entering the system is going into changing the phase of the water instead of increasing its temperature. Once the ice has melted, the temperature rises again, this time at a different rate than before because water has a different specific heat capacity than ice.
Then I think you are finished. As you say, you cannot determine the heat capacities of the water sample in its different phases, let alone the capacities per unit mass. All you can provide is the ratios between them.
 

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