Atoms of the inert gas Krypton are adsorbed onto a smooth solid
surface at 90K. They can move freely over the surface but they cannot leave it. For a
sample with total surface area 2.5 m^2, and a surface density 3 nm-2, what is the heat
capacity of the krypton?
[itex]\Delta E[/itex]/ [itex]\Delta T[/itex] = Cv ( where Cv is specific heat @ constant volume)
[itex]\Delta E[/itex] = [itex]\Delta W[/itex] + [itex]\DeltaQ[/itex]
U = 3/2nRT , U = 3/2NkbT
The Attempt at a Solution
Krypton molecular weight : 84.8 /1000 = 0.0848 kg/mol.
I believe I have an idea on how to solve this. The fact that the gases can't escape implies work done = 0, however I am a little confused by the spatial dimensions provided.
Would I multiply 2.5 with 3 ? however that makes no sense to get mass. I was wondering.. could I use : Mass = Molecular weight / Avogadro's number and then plug in: Moles = mass/mr to give me 'n' which I could plug into U = 3/2nRT
Is my approach sensible ?