Heat transfer rate to heating time

AI Thread Summary
The discussion focuses on calculating the heat transfer rate (Q) for a system where a cylindrical outer wall at 500°C heats a gas, which then heats a central cylindrical metal block starting at 20°C. The calculated heat transfer rate is 11.3213 Watts, which the user questions as potentially low. To relate heat transfer to time, the user employs the equation q=cmΔT, where c is the specific heat of the gas, m is its mass, and ΔT is the temperature change. The user seeks assistance in refining the equation and understanding the model variables, as well as requesting additional information via email. The conversation emphasizes the need for clarity in heat transfer calculations and their implications for heating time.
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i have set up an equation to get the heat transfer rate Q for a combined system where heat is transferred from a cylindrical outer wall set at 500 C. the wall heats a gas, which in turn heats a solid block of cylindrical metal positioned in the centre of the heated walls with a starting temperature of 20 C.

the equation i have is

Q=[1]\frac{}{}[/(A0/(h*Alm1))+((r*A0)/(k*A2))+(A0/(h*Alm3))+((r*A0)/(k*A4))+(A0/(h*Alm5))]*A0*\DeltaT

and it give a result of 11.3213 Watts or the situation above.

but too me this seems small?? am i right in thinking this?

also can anyone tell me how i can relate this heat transfer to time. ie. know how long it would take to heat the central metal part.

Thank you in advance.
 
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could you fix the latex?
 
i could not get the equation editor to work properly (probaly the user to be fair) but i am included a hand written version as an attachment. i have managed to modifie it a bit which is giving me more sensible answers. But to get a value for time (in seconds#) i am using the below equation to get a value for q in joulse and then dividing q by Q.

q=cm\DeltaT

c = specific heat of the gas
m = mass of gas
delta T = the change in temperature

Thanks
 

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My email address is riscy00@googlemail.com
 
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