Heat Transferred to 8,000-kg Aluminum Flagpole

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To calculate the heat transferred to an 8,000-kg aluminum flagpole heated from 10°C to 20°C, the specific heat of aluminum (0.215 cal/g°C) is used. The formula Q=mcΔT is applied, where m is the mass in grams, c is the specific heat, and ΔT is the temperature change. The calculation yields 17,200,000 calories, which converts to approximately 72,000,000 joules. The solution is confirmed as correct by participants in the discussion. The method and final answer are validated.
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Homework Statement



An 8 000-kg aluminum flagpole 100-m long is heated by the sun from a temperature of 10°C to 20°C. Find the heat transferred (in J) to the aluminum if the specific heat of aluminum is 0.215 cal/g °C.

Homework Equations



Q=mc delta T

The Attempt at a Solution



(8000000g)(.215cal/g)(10)

so i get 17200000 cal convert to J
7.2e7 J

is that correct??
 
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i think so
 
Looks good to me too.
 

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