• Support PF! Buy your school textbooks, materials and every day products via PF Here!

Hello, my name is matt and i have a problem. please help

  • Thread starter flutieflakes
  • Start date

flutieflakes

howdy. i'm not too good at physics, and i have a lab due tomorrow. it isn't too complex of a problem, so help would be appreciated. if you are willing to help, say "asyemptote" and i will type the problem. thanks a bundle
 

Integral

Staff Emeritus
Science Advisor
Gold Member
7,185
55
If you have a question, post it. If not get to work on your lab.
 

flutieflakes

ok here it is (i just wanted to see if anyone was still in the forum

M1 M2
| |
22cm| 78cm|
----------------------------------
6.7cm| 68cm|
| |
70g 260g

The horizontal line is a 100cm yard stick weighing 120g
The verticle lines are strings attached to weights (the ones going up are attached to pulleys)
The Lengths next to the strings are the distance from the left end of the stick to the strings.
What would I do to determine the weight of M1 and M2?
The apparatus is hanging in equilibrium.
Thanks
 

flutieflakes

that didnt work too well, but imagine the weights correspond to the lenghs above or below them. (if you still dont get it, thats ok. it's a pretty confusing diagram of it.)
 

HallsofIvy

Science Advisor
Homework Helper
41,709
876
The "torque" of a force around a point measures how much "twist" it causes about that point and is the product of the force times the distance from the point.

What you need to do here is multiply each weight time the distance of that weight from the left end (just since that is the info you are given- since this object ISN'T "twisting", it is "balanced" about any point). Be sure to take those weights hanging down to be negative and those weight over the pulleys to be positive (their pull is upward). Use "M1" and "M2" for the unknown weights. Add all of those to get the total "torque". Since the object is in equilibrium, it is not twisting and that torque must be equal to 0. That gives you one equation. Because the object is also not moving directly up or down, the net force must also be 0: ignoring the distances, add all of the weights (again, positive for those going over the pulley, negative for those hanging down) and set that equal to 0.

You now have two equations to solve for M1 and M2.
 

Related Threads for: Hello, my name is matt and i have a problem. please help

  • Posted
Replies
1
Views
1K
Replies
5
Views
531
  • Posted
Replies
1
Views
924
Replies
3
Views
312
Replies
1
Views
3K
  • Posted
Replies
7
Views
2K

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top