Solving Friction Problems: Coefficient of Kinetic & Normal Force

  • Thread starter Thread starter Graif
  • Start date Start date
AI Thread Summary
The discussion focuses on solving friction problems involving the coefficient of kinetic friction and dynamics on an incline. Participants seek assistance with two specific problems: calculating the coefficient of kinetic friction for a box sliding down a ramp and determining forces acting on a block on an incline. Key concepts mentioned include drawing free body diagrams, applying Newton's second law, and using kinematic equations to find acceleration and frictional forces. The urgency of the assignment due time is emphasized, along with a reminder for participants to show their work rather than simply asking for answers. Overall, the thread highlights the importance of understanding the underlying physics principles in solving these problems.
Graif
Messages
2
Reaction score
0
ok, I am really having trouble with Friction here, how exactly do u get the coefficient of kinetic friction? I have 2 problems here:

1)A box slides down a 31.5° ramp with an acceleration of 1.28 m/s2. Determine the coefficient of kinetic friction between the box and the ramp.
Answer: ?

2)A 3.20 kg block starts from rest at the top of a 30.0° incline and slides 2.20 m down the incline in 1.50 s.

(a) Find the acceleration of the block.
Answer: 1.96 m/s^2
(b) Find the coefficient of kinetic friction between the block and the incline.
Answer: ??
(c) Find the frictional force acting on the block.
Answer: ?
(d) Find the speed of the block after it has slid a distance of 2.20 m.
Answer: 2.94 m/s
Now I also have a normal dynamics/kinematics problem which i though i knew, but webassign keeps marking it wrong. here it is:

3) A block with a mass of 20 kg is held in equilibrium on an incline of angle = 30.0° by the horizontal force, F, as shown in Figure 4-31. Find the magnitude of F.
Answer: ?
Find the normal force exerted by the incline on the block. (Disregard friction.)
Answer: ?

Figure 4-31 is just a ramp (a right triangle) with a cube above it, and the F arrow is horizontally poiting to the right above the cube.

This assigment is due today at 7am, if anybody can help me, please anwer this threat or IM me to aim(cronowarrior007) or yahoo (coolkegcomputer) or MSN (coolcomputer7@hotmail.com).

Thanks so much :smile:
 
Physics news on Phys.org
Dont post twice please. Becomes anyoing reading same thing two times. Thank you.
 
We're not going to do your homework, so start showing us your work.

Remember,

-Draw Free Body Diagram

Friction Force
F_{f} = \mu N

Newton's 2nd Law
\sum^{n}_{i=1} \vec{F}_{i} = m \vec{a}
 
Last edited:
Also,

D = V_it + \frac{1}{2}at^2

(Hint: rearrange the equation.)

Hope that helps!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top