HELP finding FORCE OF FRICTION?

AI Thread Summary
To find the force of friction acting on a 4.24 kg block being pulled up a ramp, it's important to analyze the forces involved. The normal force of 9.21 N suggests a steep incline, approximately 77 degrees. The "motion" force of 3.5 N indicates that the block is being pulled at a constant velocity, meaning the net force is zero. To maintain this constant velocity, the pulling force must overcome both gravity and friction, implying that the actual force needed is greater than 3.5 N. Understanding the components of forces parallel and perpendicular to the ramp is crucial for solving this problem accurately.
dagitt
Messages
6
Reaction score
0
HELP finding FORCE OF FRICTION?

1. I'm pulling a 4.24kg block UP a ramp.
2. The normal force is 9.21 N.
3. The "motion" force as it is being pulled up the ramp at constant velocity is 3.5 N.

What is the force of friction acting on the block??



Please help...I've pondered over this prob and I'm confused as to what formulas to use, etc...
 
Physics news on Phys.org


Are you sure the normal force is 9.21N? That would be a quite steep ramp.
What exactly is the "motion" force? The velocity is constant, so the net force is 0.
The force that you use to pull must overcome both gravity and friction and has to be
much bigger than 3.5N to do that.

With nearly all slope problems you have to split the forces involved in components parallel and perpendicular to the slope.
 


Are you sure the normal force is 9.21N? That would be a quite steep ramp.
What exactly is the "motion" force? The velocity is constant, so the net force is 0.
The force that you use to pull must overcome both gravity and friction and has to be
much bigger than 3.5N to do that.

With nearly all slope problems you have to split the forces involved in components parallel and perpendicular to the slope.
 


Ya, with a normal force like that, the plane must be inclined around 77 degrees. That's steep!
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top