Help I dunno how to use coefficient

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The discussion centers on calculating the force of friction, net force, and acceleration for a 20 kg mass subjected to a 150 N force with a coefficient of kinetic friction of 0.10. Participants express confusion about how to incorporate the coefficient of friction into their calculations and how it relates to the forces acting on the mass. A force diagram is attempted, but the user struggles to accurately represent the forces involved. The frictional force is noted to oppose the applied force, and there is a question about the direction of the friction force in relation to the downward force. Overall, the thread highlights a need for clarity on applying friction coefficients in physics problems.
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Help... I don't know how to use coefficient!

Homework Statement


A 20 kg mass is moving along a horizontal surface. A 150 N force is applied to it. If the coefficient of kinetic friction is 0.10, calculate
a) The force of friction
b)The net force
c)The acceleration
Draw a force diagram

The Attempt at a Solution



Well, I don't know how to calculate a-c, but I attempted to draw a force diagram of it:

Since I cannot post it, i will describe how it looks:
A block is on the surface of the floor. It has a force of 200 N pushing down on the ground, and the push of 150 N pushing the object. The resulting force is 240 N, if measured by scale diagram. Thats about as far as I got. Please help...:cry:
 
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theLHC said:

Homework Statement


A 20 kg mass is moving along a horizontal surface. A 150 N force is applied to it. If the coefficient of kinetic friction is 0.10, calculate
a) The force of friction
b)The net force
c)The acceleration
Draw a force diagram

The Attempt at a Solution



Well, I don't know how to calculate a-c, but I attempted to draw a force diagram of it:

Since I cannot post it, i will describe how it looks:
A block is on the surface of the floor. It has a force of 200 N pushing down on the ground, and the push of 150 N pushing the object. The resulting force is 240 N, if measured by scale diagram. Thats about as far as I got. Please help...:cry:

The coefficient of friction will apply to the force between the block and the surface. And this would have a relationship with the 200N downward force. But it's effect would serve to retard the 150N horizontal force.
 


well how can you put this into a summation equation?
where does the friction coefficient go into the equation?
 


theLHC said:
well how can you put this into a summation equation?
where does the friction coefficient go into the equation?

What is the frictional force? Is it easier to drag a wooden box of books over the carpet or over an ice rink surface?

If the coefficient of friction applies to its downward force, what direction does it act.
 


well, i guess it acts in the downward direction?
 

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