Help in Solving a problem using F.T.C

  • Thread starter Thread starter lilypeach
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on using the Fundamental Theorem of Calculus to evaluate the definite integral of the function 5/(x²+1) from -1 to 1. The correct antiderivative is identified as 5 * arctan(x), and the user initially misapplies the integral notation. The final evaluation of the integral results in a correct value, but the user mistakenly arrives at 450 due to a misunderstanding of the integration process. The importance of using radians in trigonometric functions is also emphasized.

PREREQUISITES
  • Understanding of the Fundamental Theorem of Calculus
  • Knowledge of trigonometric functions, specifically arctangent
  • Familiarity with definite integrals and their evaluation
  • Basic calculus notation and operations
NEXT STEPS
  • Review the Fundamental Theorem of Calculus and its applications
  • Study the properties and applications of the arctangent function
  • Practice evaluating definite integrals with trigonometric functions
  • Learn about the significance of radians in calculus
USEFUL FOR

Students and educators in calculus, mathematicians, and anyone seeking to improve their understanding of integration techniques and the Fundamental Theorem of Calculus.

lilypeach
Messages
6
Reaction score
0
Hi, here's my problem



Use the Fundamental Theorem of Calculus to evaluate the definite integral.
from the int. of -1 to 1, with the function being 5/x^2+1

= 5 int. 1/x^2+1
= 5 int. tan^(-1)(x)
= 5 x tan^-1(x)
Plug in 1 and -1...subtract...= 450, except it's wrong.

I've gotten as far as 5 int. tan^-1(x), and I get 450 once I plug in the limits, Am I missing anything?
 
Physics news on Phys.org
lilypeach said:
Hi, here's my problem
Use the Fundamental Theorem of Calculus to evaluate the definite integral.
from the int. of -1 to 1, with the function being 5/x^2+1

= 5 int. 1/x^2+1
You need parentheses if you mean an integrand of 1/(x2+1)
= 5 int. tan^(-1)(x)

And if you have taken the antiderivative, you shouldn't still have the "int" in front.
= 5 x tan^-1(x)

And where did the x in front come from?

Plug in 1 and -1...subtract...= 450, except it's wrong.

I've gotten as far as 5 int. tan^-1(x), and I get 450 once I plug in the limits, Am I missing anything?

That last antiderivative, somehow, is actually correct. But remember in derivatives and integrals of trig function, x is always in radians.
 
excellent, got it.

Thanks a million.
 

Similar threads

Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
7
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K