Why Should the Boat Head in a Specific Direction to Cross the River Quickly?

  • Thread starter Thread starter mikeyman2010
  • Start date Start date
AI Thread Summary
To cross a river quickly against an eastward current, the boat should head directly north. This approach maximizes the northward component of the boat's speed, ensuring the fastest crossing time. While heading northwest might seem to minimize the distance traveled, it actually results in wasted speed moving sideways against the current. The key factor is to prioritize the speed of crossing rather than the total distance traveled. Therefore, the optimal strategy is to go straight north, allowing the current to carry the boat downstream while maintaining a direct path across the river.
mikeyman2010
Messages
18
Reaction score
0
Hey, I'm a high school physics student and I came across this question on one of my practice papers that stumbled me quite a bit. It's a relatively simple relativity/vector question, but I can't understand why the correct answer is what it is. Can any1 help me?

Here's the question:

Suppose we have a river, and a boat is trying to get to the other shore. A current is blowing to the east. In what direction should the boat head to arrive at the other end of the river in the shortest time?
a) North
b) Northeast
c) Northwest


___________________________________________________________

Current---------->




__
/ \
[ ]
[ ]
__________________________[____]_________________________
 
Physics news on Phys.org
Does it matter where it ends up on the other side, i.e. does it have to end up directly across from it's starting position? If it has to be directly across, then it's only choice is to go Northwest. If it just has to get to the other side, then "North" is the correct answer. Why? Because the effect of the current only affects how fast it goes east/west, it has no north component. So, the speed at which it goes north depends solely on the north component of the rowing speed (the speed of the boat if it were in still water). Since going straight north gives the greatest possible north component, north is your answer.
 
Thnx for the reply. I don't think where the boat lands matters, but i'd like to know, if you go north directly, wouldn't the distance you need to travel to reach the opposite shore increase since current blows you off-course? (Since it's a hypotenuse side of a right triangle). I thought it was going northwest would give you the shortest time since it minimizes the distance you need to travel by allowing the current to blow you into a straight path. Can you explain why having a greater velocity matters more than having a shorter distance to travel to travel across the river? Again, thnx for the help!
 
mikeyman2010 said:
I don't think where the boat lands matters, but i'd like to know, if you go north directly, wouldn't the distance you need to travel to reach the opposite shore increase since current blows you off-course? (Since it's a hypotenuse side of a right triangle).
Sure you'll travel a greater distance, but who cares? All you care about is traveling as fast as possible in the North direction. You want to minimize the time it takes to get you across the river, not the total distance you travel.
I thought it was going northwest would give you the shortest time since it minimizes the distance you need to travel by allowing the current to blow you into a straight path.
It does minimize the distance, but you waste speed going sideways. So it ends up taking you longer to cross.
Can you explain why having a greater velocity matters more than having a shorter distance to travel to travel across the river?
The only distance that matters is the distance across the river (south to north), not the total distance traveled. That south to north distance doesn't change. And you want to traverse that distance as fast as possible. So don't waste any speed fighting the current. Make sense?
 
Oh, i see, so even if you go straight, and get blown off-course, the distance you travel from south to north stays the same, right?
 
Exactly right!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .

Similar threads

Replies
4
Views
3K
Replies
8
Views
10K
Replies
22
Views
5K
Replies
4
Views
2K
Replies
29
Views
3K
Replies
6
Views
2K
Replies
1
Views
3K
Back
Top