Help with a SDOF system, spring and base?

AI Thread Summary
The discussion revolves around solving a single degree of freedom (SDOF) system involving a spring and base displacement. The user is trying to understand the equations governing the system, particularly the step response equation, and is uncertain about the differences between parts a and b of their homework. For part a, the correct equation is identified, while part b requires inputting a step function into the differential equation to solve for displacement over time. The use of Laplace transforms is suggested for solving the differential equation, and there's a recommendation to clarify the initial conditions for the system. Overall, the conversation emphasizes the importance of correctly applying the equations and understanding the step response in dynamic systems.
lupinpooter
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Homework Statement


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Homework Equations


Maybe the step response equation?
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The Attempt at a Solution


I don't really understand the difference between a and b, but he said part a was supposed to be quite easy. Is a just:
mx'' = -k(x-y) - c(x' - y')
or something along those lines? where x represents the displacement of the seat, and y the displacement of the base, so y' = 4cm? or y = 4cm?

Using F0= k * 0.04, and plugging the values into the step response equation, with zeta = c/2m*ωn, and ωn = √ (k/m), and ωd= √(1-ζ2n, I got the graph at the bottom (I think), which makes me assume it's right, without much idea what I put for b. When it says 'develop', does this mean derive the step-response equation? Or just plug in the variables?

Any help would be appreciated. Thank you
 
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Looks like you have the right equation for part a.

For part b you should input a step into y(t) at t=0 and solve the diff. equation for x(t). I would use the Laplace transform if you're familiar with it, otherwise you'd have to grind out the classical diff. eq.

I don't know if your "step response equation" is correct. It looks plausible. I would start from scratch rather than use it unless you get a strong indication that that's what's expected of you. What would you do with the tau in it?
 
oh sorry, (t - tau) would just be t, taking tau=o as the moment that it steps
 
Last edited:
lupinpooter said:
oh sorry, (t - tau) would just be t, taking tau=o as the moment that it steps

OK, so how about F0? You don't know what that value is ...

Again, I suggest working with your part a equation.
I would let x=0 and y=0 when t<0.
 
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