Help With Gas/Liquid Pressure/Volume

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To calculate the volume of oxygen removed from a liter of water with a dissolved oxygen level of 10 mg/L, first convert 10 mg to moles using the molar mass of O2, which is approximately 32 g/mol. This results in about 0.0003125 moles of O2. Applying the ideal gas law (PV=nRT) at 1 atm and 25°C (298 K), the volume occupied by this amount of oxygen can be calculated. The final volume of the oxygen gas is approximately 7.6 liters. Understanding the relationship between gas and liquid states is crucial for accurate calculations in this context.
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1. Assume that a high dissolved oxygen level is 10 mg/L. If you have a liter (L) of water and removed all of the oxygen from it what volume would it occupy? (Use the ideal gas law and assume that P = 1 atm = 1 bar and that temperature is 25 C).



2. PV = nRT



3. Don't know how to use this equation with a gas and liquid.
 
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Brzostek said:
1. Assume that a high dissolved oxygen level is 10 mg/L. If you have a liter (L) of water and removed all of the oxygen from it what volume would it occupy? (Use the ideal gas law and assume that P = 1 atm = 1 bar and that temperature is 25 C).
So how many milligrams of O2 would be removed (assume there are 10 mg/L dissolved in the water)? How many moles of O2 is that? How much volume will that amount of O2 occupy at 1 atm = 101325 Pa. and 25C (Hint: use PV=nRT. What is the temperature in K?)?


AM
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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