Help with IntegralS Very Important Quick

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    Important Integrals
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The forum discussion revolves around a student from Ukraine seeking help with ten integration problems due to illness that caused missed lessons. The integrals include various functions such as (2*(x^(1/3))+3*x*(x^(1/2)))/(x^(1/4)) and (1-2*sinx)/(cosx^2). Participants provided guidance on techniques like integration by substitution and trigonometric substitutions, emphasizing the importance of showing work and understanding the concepts involved. The student demonstrated progress by attempting solutions and engaging with the community for further assistance.

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  • #91
So the last is 10 =)
tell please what i must take for u and what for dv...
 
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  • #92
Student from UA said:
So the last is 10 =)
tell please what i must take for u and what for dv...

Hootenanny said:
Question 10 is just another application of the product rule. Let u=(1-3x) and dv=cos(2x)

bollocks and stuff
 
  • #93
Student from UA said:
So the last is 10 =)
tell please what i must take for u and what for dv...

Post #67, and post #71 should answer that:
(1 - 3x) is an algebraic function, and cos(2x) is a trig function. The one that stands before the other in the sequence LIATE should be chosen for u, and the rest for dv. So what should be u, and dv this time?
 
  • #94
\int cos2x dx How to do?
 
  • #95
LIATE -what is it? givee me link . i want read it.
 
  • #96
Student from UA said:
\int cos2x dx How to do?

You should let u = 2x.
When you have to deal with:
\int \sin(ax + b) dx
\int \cos(ax + b) dx
\int \tan(ax + b) dx
\int e ^ {ax + b} dx
\int \frac{1}{ax + b} dx
...
You should let u = ax + b
Or, in general, when deadling all the function f(ax + b), where \int f(x) dx can be found easily, make the u-substitution u = ax + b.

LIATE -what is it? givee me link . i want read it.
It's right in the post #67. :)
 
Last edited:
  • #97
Liate -good. I will write in my note... =) very interesting rule
 
  • #98
U know.. I have done the 10th. It`s VICTORY! TAda! =)
 
  • #99
Thx! Thx To All WHo help ME to do my Home Work! U`re a very good persons and Very very Clever. And I don`t know why a lot of XXXXX say that USA - And Americans are very ... O don`t think so... U are very friendly people and can help other people in any time. One more thx. If i would have some qustions in future, i imidiatly will go to this nice foorum to nice people =) Thx a lot.!
 
  • #100
Well.. we're not all from the USA... in fact I don't think anyone who helped in this thread is!

Anyway, I'm glad you got your work done. Good luck in the future.
 
  • #101
don`t mater where are u from! becouse u are super mens =) i`m very happy that i`m find u!
 
  • #102
That was one of the funniest threads I've ever read through.
 
  • #103
BSMSMSTMSPHD said:
That was one of the funniest threads I've ever read through.
And why would you say that?
 
  • #104
It was like reading a really dramatic story that I didn't know the ending to. At times, I thought the poor guy wasn't going to get the answers he needed. But, he kept working hard, and eventually came through. Then he proclaimed VICTORY, and thanked the USA! It was straight out of Hollywood.

Usually I don't read through 100-post threads, but this was a next-clicker (page-turner).
 

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