Help with mass flow rate of turbine?

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SUMMARY

The discussion focuses on calculating the mass flow rate of air through a turbine that expands air from 1300 kPa and 500°C to 100 kPa and 127°C. The user initially calculated a mass flow rate of 58.6 kg/s using the equation m dot = (1/v)(V)(A) with a specific volume derived from the ideal gas law PV=RT. However, the expected answer is 46.9 kg/s, indicating a potential oversight in accounting for the conditions at the exhaust end of the turbine.

PREREQUISITES
  • Understanding of the ideal gas law (PV=RT)
  • Familiarity with mass flow rate calculations (m dot = (1/v)(V)(A))
  • Knowledge of thermodynamic properties of air
  • Basic principles of turbine operation and fluid dynamics
NEXT STEPS
  • Review the impact of pressure and temperature changes on specific volume in thermodynamics
  • Learn about the effects of turbine expansion on mass flow rates
  • Study the concept of conservation of mass in fluid dynamics
  • Explore advanced calculations involving compressible flow in turbines
USEFUL FOR

Mechanical engineers, thermodynamics students, and professionals involved in turbine design and analysis will benefit from this discussion.

nate9519
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Homework Statement


An turbine expands air at 1300 kPa and 500oC to 100 kPa and 127oC. Air enters the turbine through a 0.2-m2 opening with an average velocity of 50 m/s, and exhausts through a 1-m2 opening. Determine (a) the mass flow rate of air through the turbine

Homework Equations


PV=RT
m dot = (1/v)(V)(A)

The Attempt at a Solution


[/B]
I use PV=RT to get specific volume. (.287 * 773)/1300 = .17065 m^3/kg
I then plug it into the formula for mass flow rate which is (1/.17065)(50)(.2) = 58.6 kg/s
the problem is that the answer is suppose to be 46.9 kg/s but I can see anything I've done wrong. can someone help??
 
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nate9519 said:

Homework Statement


An turbine expands air at 1300 kPa and 500oC to 100 kPa and 127oC. Air enters the turbine through a 0.2-m2 opening with an average velocity of 50 m/s, and exhausts through a 1-m2 opening. Determine (a) the mass flow rate of air through the turbine

Homework Equations


PV=RT
m dot = (1/v)(V)(A)

The Attempt at a Solution


[/B]
I use PV=RT to get specific volume. (.287 * 773)/1300 = .17065 m^3/kg
I then plug it into the formula for mass flow rate which is (1/.17065)(50)(.2) = 58.6 kg/s
the problem is that the answer is suppose to be 46.9 kg/s but I can see anything I've done wrong. can someone help??
Did you check what happens at the exhaust end? The air has expanded after going thru the turbine.
 

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