1. The problem statement, all variables and given/known data An turbine expands air at 1300 kPa and 500oC to 100 kPa and 127oC. Air enters the turbine through a 0.2-m2 opening with an average velocity of 50 m/s, and exhausts through a 1-m2 opening. Determine (a) the mass flow rate of air through the turbine 2. Relevant equations PV=RT m dot = (1/v)(V)(A) 3. The attempt at a solution I use PV=RT to get specific volume. (.287 * 773)/1300 = .17065 m^3/kg I then plug it in to the formula for mass flow rate which is (1/.17065)(50)(.2) = 58.6 kg/s the problem is that the answer is suppose to be 46.9 kg/s but I can see anything Ive done wrong. can someone help??