1. The problem statement, all variables and given/known data A ball is held by a vertical tether C. The vertical tether C is held be tethers A and B (which are slanted). Tether A has an angle of 30 degrees. Tether B has an angle of 60 degrees. The ball has 150 Newtons. The system is in an equilibrium. What are the Newtons in theaters A, B, and C? 2. Relevant equations Fnet = 0 3. The attempt at a solution We know the vertical component force is equal to the two vertical components of the two slanted tethers. The two tethers' vertical components are 75 N because it is half of 150 N of the ball. sin 30 = (75 N)/ x // x is the tether A, we solve for x to get the newtons for A x sin 30 = 75 N x = (75 N)/(sin 30) x = 150 N sin 60 = (75 N)/ y // y is the tether B, we solve for x to get the newtons for B y sin 60 = 75 N y = (75 N) / (sin 60) y = 87 N The tether A has 150 Newtons and tether B has 87 Newtons and tether C has 150 Newtons. But my book says that tether A has 130 Newtons, tether B has 75 Newtons and tether C has 150 Newtons!!! I set the problem correctly though. I have an illustration of the same problem. Note they are in an equilibrium.