Help with question related to friction on an incline?

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SUMMARY

The discussion focuses on calculating the force of friction required to hold a car on a slope inclined at 4.5 degrees, with a mass of 560 kg. The calculated force of friction (Ff) is 427 N, derived using the equation Ff = u x Fn, where u is the coefficient of friction and Fn is the normal force. For part b, the coefficient of static friction (u) is determined to be 0.078, indicating the relationship between the friction force and the coefficient of friction when the car is on the verge of slipping on ice.

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Homework Statement



A car with a mass of 560 kg is parked on a hill inclined at 4.5 degrees to the horizontal.

a.) What is the force of fricton necessary to hold the car on the slope?

b.) If there is ice on the hill and the car is about to slip, what is the coefficient of static friction?

Homework Equations



Ff = u x Fn = u x mg(costheta)

The Attempt at a Solution



The answer I got for part a

a =
0 = - (9.8sin4.5 + U9.8cos4.5)
u = 0.078
Ff = (0.078)(560)(9.8)(cos4.5) Ff = 427N


I'm stuck on Part B

Thanks.
 
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hi pokeefer! :smile:
pokeefer said:
a.) What is the force of fricton necessary to hold the car on the slope?

b.) If there is ice on the hill and the car is about to slip, what is the coefficient of static friction?

I'm stuck on Part B

it's just asking for the relation between friction force and the coefficient of friction :wink:
 

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