- #1
imd25
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Hi
I was given the following problem in my coursework:
"A spring is initially compressed by 50mm when a steel ball of mass 2kg is released from just being in contact with the uncompressed spring. Determine the spring stiffness (k) of the spring."
F = mg
Restorative force F = -kx
I gave the answer below, but the teacher has marked it as wrong. Can anyone shed any light on where I may have made a mistake? I thought it was just a simple application of Hooke's Law.
F = mg
F = 2 x -9.81
F = -19.62 N
F = -kx
19.62 = -k(-0.05)
19.62 = 0.05k
k = 19.62/0.05
k = 392.4
Thanks, any insight gratefully received.
I was given the following problem in my coursework:
Homework Statement
"A spring is initially compressed by 50mm when a steel ball of mass 2kg is released from just being in contact with the uncompressed spring. Determine the spring stiffness (k) of the spring."
Homework Equations
F = mg
Restorative force F = -kx
The Attempt at a Solution
I gave the answer below, but the teacher has marked it as wrong. Can anyone shed any light on where I may have made a mistake? I thought it was just a simple application of Hooke's Law.
F = mg
F = 2 x -9.81
F = -19.62 N
F = -kx
19.62 = -k(-0.05)
19.62 = 0.05k
k = 19.62/0.05
k = 392.4
Thanks, any insight gratefully received.