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High School Physics Competition: Change in Entropy

  • Thread starter ReneG
  • Start date
  • #1
4
1
During a physics competition, I came across this question.
What is the change in entropy of the system when 1.25 " 103 J of heat is added to the system that is maintained at a constant 75.0 C?
My work was
[itex]\begin{align*}\Delta S &= \frac{Q}{T} \\ \Delta S &= \frac{1.25 \times 10^3 \, \mathrm{J}}{348 \, \mathrm{K}} \\ \Delta S &= 3.59 \,\,\mathrm{\left( J/K\right )} \end{align*}[/itex]

but I was stuck in between two answer choices

c) + 3.59 J/K
d) # 3.59 J/K

I had no idea what the hashtag meant, so I skipped it. Can someone clear this up for me?
 

Answers and Replies

  • #2
537
146
Honestly I have no idea, but certainly the change in entropy is positive, so answer c) is correct. Maybe it's a misprint?
 
  • #3
3
0
I guess what dipole said it's right 'cause it sometimes happens
 
Last edited:
  • #4
4
1
For anyone who was wondering, the hashtag just meant "negative". Thank you dipole.
 

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