Hocky puck vel/displacement/acc

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A horizontal air table can support hockey pucks, allowing them to move with minimal friction. A puck with a mass of 0.250 kg is pushed by a 1.00 N force for 2.00 seconds, prompting a discussion on calculating its acceleration, final velocity, and displacement. The correct formula for acceleration is derived from Newton's second law, f=ma, leading to an acceleration of 4 m/s². The user initially struggled with the equations but ultimately clarified their approach. The calculations for velocity and displacement will follow from this established acceleration.
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1. By pumping air up through thousands of tiny holes we can make a horizontal air table that will support several pucks so that they can move around on cushions of air with very little friction. Suppose that one such puck initially at rest, having a mass of 0.250 kg, is pushed along by a 1.00 N force for 2.00 s. Determine its acceleration and the final velocity at the end of 2.00 s. What will be the displacement?



2. Well, of all the equations that I thought I should use, I thought it would be Acceleration=(Velocity final-Velocity initial)/(time)



3. I've made several attempts at a solution but I'm not sure if I'm using the right equation, someone mind pushing me in the right path?
 
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Never mind. I figured out that f=ma and I know the force and the mass. No biggy :)
The rest will be easy to figure out, thanks :)
Though, it would be (1 kg m/s^2)/ (.250 kg) = 4 m/s^2, correct?
 
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