Solving Two Acceleration Problems: Homework Help Needed!

[Martis31]

so here are the two problems:

1. a sports car accelerates from rest to 95 km/h in 6.2 s. What is its average acceleration in m/s2-->SQUARED?

2. a sprinter accelerates from rest to 10.0m/s in 1.32s. what is her acceleration(a) in m/s2, and (b) in km/h2?

plsss help me i need procedure so i can understand the explanation thanksss!

 

[whozum]

Definition of average acceleration

$$a_{avg} = \frac{\Delta v}{\Delta t} \ or \ \frac{v_f-v_i}{t_f-t_i}$$

You are given changes in velocity and changes in time. Simply divide.

 

[quicknote]

Hello! I am happy to help you with these two acceleration problems. Solving acceleration problems involves using the formula a = (vf - vi)/t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

For the first problem, we are given the final velocity (95 km/h) and the time (6.2 s), but we need to convert the units to match the formula. We know that 1 km = 1000 m, so 95 km = 95,000 m. We also know that 1 h = 3600 s, so 6.2 s = 6.2/3600 h. Now we can plug these values into the formula:

a = (95,000 m/6.2/3600 h) = (95,000 m/6.2 s) x (3600 s/1 h) = 15322.58 m/s^2.

Therefore, the average acceleration of the sports car is 15322.58 m/s^2.

For the second problem, we are given the final velocity (10.0 m/s) and the time (1.32 s). Again, we need to convert the units to match the formula. We know that 1 km = 1000 m, so 10.0 m = 10/1000 km. Now we can plug these values into the formula:

a = ((10/1000 km - 0 km)/1.32 s) = (10/1000 km/1.32 s) = 7.58 km/h^2.

Therefore, the acceleration of the sprinter is 7.58 km/h^2.

I hope this helps you understand the procedure and the explanation. If you have any further questions, please let me know. Good luck with your homework!