How Can Similar Triangles Help Prove Light Interference Formulas?

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To prove the formula sin(b_n)=(n*lambda)/d in the context of monochromatic light interference, the relationship between the distance between adjacent light spots (dX), the wavelength (lambda), the distance between screens (L), and the gap distance (d) is crucial. A right triangle can be constructed where n*dX represents one side and L represents the other. Using the Pythagorean theorem, the hypotenuse D can be expressed as D=sqrt(L^2+n^2*(dX)^2). The sine function can then be related to these dimensions, leading to sin(b_n)=(n*dX)/D, but further algebraic manipulation is needed to derive the desired formula. Understanding the approximation that for small angles, sin(b_n) is approximately equal to b_n can also aid in simplifying the proof.
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i need to prove that sin(b_n)=(n*lambda)/d
while dX=(lambda*L)/d

this is a situation of monochromatic light inteference where dX is the is the distance between every adjacent light spots, lambda is ofcourse the light wavelength, L is the width between the two screens, d is the distance between the gaps of first screen and n describes the place of light spots.

i know it's rather simple but my text doesn't reveal all the simple algebraic and trigonometric tricks.
but i think that if we were to build a right triangle then n*dX equals one of its sides while L is the other and by pythogrean sentence the hypotenuse equals:
D=sqrt(L^2+n^2*(dX)^2)
and then sin(b_n)=(n*dX)/D
but this is as far as i went and i didn't get the formula i needed to prove, your input is appreciated.
 
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