Sagar_C
- 30
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Okay, so in view of the helpful comments let me rewrite the paradox and the way I was trying to solve it.
The paradox: There are two trains T1 and T2 of equal rest length "L" (say) running on two parallel tracks in opposite direction with a relative velocity V such that due to length contraction one appears of length L/2 w.r.t. the other. Train T1 has a gun right at the "back end" which can shoot perpendicularly right towards the track of train T2. Suppose, it has been arranged for the the gun to shoot at the same time when the front of T1 passed the rear of T2 according to T1 clocks. Now one can see that in the frame of T1, T2 will appear contracted (to L/2) so that T2's front wouldn't have crossed the back-end of T1 when gun shoots, and thus gunshot will not hit T2. But in the frame of reference of T2, T1 will appear contracted (to L/2) and thus, the gunshot will hit T2. So is T2 hit or not hit?
My solution:
Let us define there different events:
Event E0: Tip of T1 meets tip of T2.
Event E1: Tip of T1 meets tail of T2.
Event E2: Tail of T1 meets tip of T2.
Event E3: Tail of T1 meets tail of T2.
Event E4: Gun at tail of T1 shoots at T2.
We choose E0 as the point where origins of both the frames of references of T1 and T2 coincide.
Now I argue when E4 occurs between E2 and E3, the bullet from the gun in the tail of T1 will shoot T2.
In the frame of reference of T1: T2 has length L/2 (velocity is, say, v=√3/2 in the units of c). Time when E1 occurs is t1=L/2v and time when E2 occurs is t2=L/v. The time when E3 occurs is t3=(L+L/2)/v=3L/2v. In this frame, E4 by design occurs when E1 occurs i.e. at t4=L/2v. Since t4 doesn't lie between t2 and t4. Actually, t4<t2,t3. Hence, Bullets doesn't hit T2.
In the frame of reference of T2: T1 has length L/2. Time when E1 occurs is t1'=L/v and time when E2 occurs is t2'=L/2v. E3 occurs at t3'=3L/2v. Finding t4' corresponding to E4 is what remains now. E1 and E4 are simultaneous in T1's reference frame but not so in T2's frame. It can be argued (by simple thought experiment) that E4 actually occurs before E1 in T2's frame. Using either thought experiment and Lorentz transformations, I end up finding t4'=-L/2v: t4'<t2',t3'. Bullets doesn't hit T2. (PLEASE ALSO SEE POST 54).
Thanks for cooperating with me.
The paradox: There are two trains T1 and T2 of equal rest length "L" (say) running on two parallel tracks in opposite direction with a relative velocity V such that due to length contraction one appears of length L/2 w.r.t. the other. Train T1 has a gun right at the "back end" which can shoot perpendicularly right towards the track of train T2. Suppose, it has been arranged for the the gun to shoot at the same time when the front of T1 passed the rear of T2 according to T1 clocks. Now one can see that in the frame of T1, T2 will appear contracted (to L/2) so that T2's front wouldn't have crossed the back-end of T1 when gun shoots, and thus gunshot will not hit T2. But in the frame of reference of T2, T1 will appear contracted (to L/2) and thus, the gunshot will hit T2. So is T2 hit or not hit?
My solution:
Let us define there different events:
Event E0: Tip of T1 meets tip of T2.
Event E1: Tip of T1 meets tail of T2.
Event E2: Tail of T1 meets tip of T2.
Event E3: Tail of T1 meets tail of T2.
Event E4: Gun at tail of T1 shoots at T2.
We choose E0 as the point where origins of both the frames of references of T1 and T2 coincide.
Now I argue when E4 occurs between E2 and E3, the bullet from the gun in the tail of T1 will shoot T2.
In the frame of reference of T1: T2 has length L/2 (velocity is, say, v=√3/2 in the units of c). Time when E1 occurs is t1=L/2v and time when E2 occurs is t2=L/v. The time when E3 occurs is t3=(L+L/2)/v=3L/2v. In this frame, E4 by design occurs when E1 occurs i.e. at t4=L/2v. Since t4 doesn't lie between t2 and t4. Actually, t4<t2,t3. Hence, Bullets doesn't hit T2.
In the frame of reference of T2: T1 has length L/2. Time when E1 occurs is t1'=L/v and time when E2 occurs is t2'=L/2v. E3 occurs at t3'=3L/2v. Finding t4' corresponding to E4 is what remains now. E1 and E4 are simultaneous in T1's reference frame but not so in T2's frame. It can be argued (by simple thought experiment) that E4 actually occurs before E1 in T2's frame. Using either thought experiment and Lorentz transformations, I end up finding t4'=-L/2v: t4'<t2',t3'. Bullets doesn't hit T2. (PLEASE ALSO SEE POST 54).
Thanks for cooperating with me.
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