How Can We Calculate the Pressure Inside a Sphere With Varying Density Gas?

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To calculate the pressure inside a sphere with varying gas density, the density formula used is ρ=ρo*(1-r/R), where R is the sphere's radius (5*10^10 m) and r is the variable radius. The mass of the sphere is given as M=3.3*10^50 kg, and the gas is considered ideal with a molar mass of 2.7 g/mol. The approach involves calculating the gravitational force of an infinitesimal layer within the sphere and using it to derive the pressure differential dp. The final pressure function p(r) is obtained through integration, allowing for the evaluation of pressure at the center of the sphere. The method appears sound, but verification of calculations and assumptions is recommended.
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Homework Statement



I have a sphere filled with unknown gas. I have to estimate the pressure inside of it.

  • The tricky part is that density of the sphere changes as we go deeper inside of it with the given formula:
    ρ=ρo*(1-r/R), where R is radius of the sphere and is known: R=5*1010m, and r is a variable.
  • Gas has mol mass m=2.7 g/mol.
  • Mass of the whole sphere is M=3.3*1050 kg.
  • Gas is ideal.

Homework Equations



  • pV=nRT
  • p=F/A


The Attempt at a Solution



The force of gravity of an infinitesimal layer of thickness dr inside the sphere at some radius r caused by the inner sphere is:

dF=GmM/r2 where m is the mass of the infinitesimal layer and M is the mass of inner part of the sphere.

Mass m=V*ρ=4*PI*r2o*(1-r/R)*dr
Mass M=4/3*PI*r3o*(1-r/R)

so dF=G*16/3*PI2*r3o2*(1-r/R)2*dr

dp=dF/A
dp=dF/4*PI*r2
dp=4/3*PI*G*ρo2*(1-r/R)2*r*dr

so
p(r)=4/3*PI*G*ρo2*\int(1-r/R)2*r*dr from r to R

After making the calculations I will put p(r=0) and get the pressure inside the sphere. Is my method good?
 
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