How Can You Find the Electric Field E with Given Conditions?

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To find the electric field E given the conditions of an electron with an initial velocity of (11.0 j + 16.0 k) km/s and a constant acceleration of (2.00 x 10^12 m/s²) i in a magnetic field B = (400 µT) i, the force F can be calculated using F = q(v x B). The calculations yield a force of F = 4.88 x 10^-28 i N. Using the equation E = F/q, where q is the charge of the electron, results in an electric field E of approximately 442 N/C. The calculations demonstrate the relationship between electric and magnetic forces acting on a charged particle in motion.
Sanjay101
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1. An electron has an initial velocity of (11.0 j + 16.0 k) km/s and a constant acceleration of (2.00 1012 m/s2) i in a region in which uniform electric and magnetic fields are present. If B = (400 µT) i, find the electric field E.
i. j. k2. F=ma
F=qv cross B
3. I tried finding F through one of the ways listed above, and tried using F=Eq equation to get E. However, i got different values for the force and cannot seem to get the answer.
 
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F = qv x B F = 11.0e-31 x (11.0, 16.0, 0) x (4 x 10-6, 0, 0) F = 4.88e-28 i + 0 j + 0 kE = F/q E = 4.88e-28/11.0e-31 E = 4.42 x 10^2 N/C or 442 N/C
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

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