How Do Complex Number Operations Affect Results?

Ry122
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How do I express the following in the form a+ib?

(\sqrt{-4} - 1) (\sqrt{-9})

My attempt:
(2i - 1)(3i)
6i-3i = 3i
 
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Close, but (2i)(3i)=6i2=-6, not 6i.
 
Can you tell me why the answer -6-+3i has plus or minus 3i?

Also can you tell me the answer to (3+i)^2 - (3+i)^2
The answer I got was 0.
9+6i+i^2-9-6i-i^2=0
 
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You have to define what you mean by sqrt(-n) for n>0. You could choose it to be either i*sqrt(n) or -i*sqrt(n). That's your sign ambiguity.
 
Ry122 said:
Can you tell me why the answer -6-+3i has plus or minus 3i?
What was that the answer to?? Surely not the (2i-1)(3i) problem you were just talking about!

Also can you tell me the answer to (3+i)^2 - (3+i)^2
The answer I got was 0.
9+6i+i^2-9-6i-i^2=0
The answer to a2- a2 is 0 no matter what a is!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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