How Do Force and Friction Affect a Rolling Wheel's Motion?

AI Thread Summary
A 3kg solid wheel is rolling without slipping on a horizontal surface, with a rotational inertia of (MR^2)/2. An applied force causes the wheel to accelerate at 2.0 m/s², and the discussion assumes this force is horizontal and applied at the center of the wheel. Participants suggest using Newton's second law to calculate the magnitudes of both the applied force and the frictional force. The visualization of the wheel rolling to the right helps clarify the problem. The conversation concludes with the user expressing intent to solve the problem based on the provided guidance.
brad sue
Messages
270
Reaction score
0
HI ,I don't get the correct answer the the following problem.


A 3kg solid wheel , rolling without slipping on a horizontal surface has a rotational inertia about its given by (MR^2)/2, where M is its mass and R its radius, A force applied to the axle and the center of mass has an acceleration of 2.0m/s^2.
What are the magnitudes of the applied force and the frictional force of the surface?


Here I can not visualize how the force is applied

Thank you
 
Physics news on Phys.org
Although not specified, I assume the applied force is horizontal. So I visualize the setup like so: Imagine the disk rolling to the right. The force is applied directly at the center of the disk (imagine a chain attached to the axle) and points to the right. You are given the acceleration. Use that info to figure out the forces (using Newton's 2nd law).
 
Doc Al said:
Although not specified, I assume the applied force is horizontal. So I visualize the setup like so: Imagine the disk rolling to the right. The force is applied directly at the center of the disk (imagine a chain attached to the axle) and points to the right. You are given the acceleration. Use that info to figure out the forces (using Newton's 2nd law).

OK thanks Doc. Now I will try to solve it!

B
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top