Automotive How do I calculate required torque for two dc motors?

AI Thread Summary
To calculate the required torque for two DC motors in a handicapped golf vehicle, the key equations involve determining rolling resistance, grade resistance, and acceleration force. The total tractive effort is derived from the sum of these forces. The torque can then be calculated using the formula that incorporates a friction factor and the radius of the drive wheel. For accuracy, it's suggested to adjust the acceleration force equation to include the gross vehicle mass multiplied by acceleration. Incorporating a mass factor for rotational inertia is also recommended for a more precise calculation.
Kaylin
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Hi,
I am doing a design project but I'm kinda stuck with choosing motors because i am not sure of the required torque. My project is a handicapped golf vehicle powered by 2 motors, so it would need to be able of climbing steep gradients.
I currently have an equation but I am not entirely sure if it's right.
It consist of :
1. Rolling resistance = (Gross Vehicle Mass) X (Co-efficient of Rolling Resistance)
2. Grade resistance = (Gross Vehicle Mass) X ( Sin(angle of max gradient) )
3. Acceleration force = (Gross Vehicle Mass/Gravity) X Acceleration
Adding all 3 up to give you Total Tractive Effort.

That's then used in the equation
Torque = (Friction factor for bearings and axles, etc.) X (Total Tractive Effort) X (Radius of drive wheel)

My question is, are these equations right or do I need to use more complicated equations dealing with moment of inertia, etc.

Thank you!
 
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These are the right equations to use.

To take into account the rotational inertia, you only need to add a mass factor to the third equation. More info on this page.
 
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Kaylin said:
3. Acceleration force = (Gross Vehicle Mass/Gravity) X Acceleration

I think that should be..
Acceleration force = Gross Vehicle Mass X Acceleration
 
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jack action said:
These are the right equations to use.

To take into account the rotational inertia, you only need to add a mass factor to the third equation. More info on this page.
Sorry for the late reply; but thank you.
 
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