How do I evaluate this trigonometric integral involving cosine?

whatlifeforme
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Homework Statement


evaluate the integral.


Homework Equations


integral (pi/6 to pi/4) [(sin2x)^4 / sqrt(1-cos2x) dx]


The Attempt at a Solution


1. multiplying by conjugate: sqrt(1+cos2x)/sqrt(1+cos2x) .
2. should i split the (sin2x)^4 into (1-(cos2x)^2)^2 ?
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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