How Do I Find the Angle of Force in This Scenario?

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Homework Help Overview

The discussion revolves around determining the angle at which a woman pulls a rock using a rope, given specific forces and acceleration. The problem involves concepts from dynamics, particularly relating to forces and angles in a pulling scenario.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between force, mass, and acceleration, questioning the adequacy of the initial force provided. There is an attempt to apply trigonometric relationships to find the angle but confusion arises regarding the calculations and the values used.

Discussion Status

The discussion has seen participants correcting initial values and attempting to derive the angle using trigonometric functions. Some guidance has been offered regarding the calculations, and there is a recognition of the need for accurate values to proceed effectively.

Contextual Notes

Participants note discrepancies in the initial problem setup, including potential errors in the force and mass values, which affect the calculations. The context of homework constraints is implied, as participants are working through the problem without providing direct solutions.

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Homework Statement



Question in angle of force: A women is pulling a rock attached to a rope with 10N of force. If the mass of the rope&rock is 30 kg. And if the rope&rock accelerate at 5 m/s squared without friction. What is the angle to the horizonal ground does the woman pull?



Homework Equations



Mass= 30kg
Fnet=10N
A=5m/s^2

The Attempt at a Solution




What I tried to do was use this forumula: (m)(a)=(Fnet)Cos(theta)-Ff

So then I tried to do the 30*5 which is 150 = 10cos-1 But I could find the angle.

I do not know how to corrently find the angle in these types of questions.




thanks!
 
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150 = 10cos(θ)
15 = cos(θ)
but there is no solution. This is because you need more than 10 N to accelerate 30 kg at 5 m/s². In fact, you need 150 N when pulling straight ahead. Is it possible you have copied a number in the question incorrectly?
 
Yes sorry I did, it is f40N, m=10kg, a=3.5ms/s/s

I was looking at a different quesion. I just cannot seem to find a way to find the angle. I tried drawing a diagram to no avail.
 
F=ma
40*cos(Θ) = 10*3.5
cos(Θ) = 35/40
cos(Θ) = 0.875
Now take the inverse cosine of both sides to get
Θ = invCos(0.875)
Θ = 29 degrees
 
Thanks! Now I will know how to find the Θ for my next questions like this. Thanks again, appreciate it.
 
Most welcome!
 

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