How do I sketch a direction field for Newton's 2nd law with a constant added?

XSK
Messages
7
Reaction score
0

Homework Statement



(i'm not sure if this is the correct forum please move it if incorrect)
my problem is with generally drawing direction fields - i don't really know what to do. i have notes but i can't make head nor tail of them. this is an example of a question concerning them:

veloc.png


Homework Equations



i know that if you stick the requirments into Newton's 2nd law adding constant k you get that equation, and i know to find the terminal velocity you integrate and find v, but i don't know how to sketch the direction field.

The Attempt at a Solution



i see that

dv/dt = -g + k/m

but this seems to be independant of both v and t so how do i plot it as a graph?

even if there were a v or t in that equation i still wouldn't be comfortable to draw the direction field because i don't know what to do >_>;

thanks
 
Last edited:
Physics news on Phys.org
Think of direction fields as a {dy \over dx} = f(x,y). At each point (x,y) on the graph, you draw a tic-mark with slope equal to f(x,y). So here, instead of x and y, we have v and t, and f(v,t)=-g+k/m. What's the slope of each tick mark going to be?
 
uhh
i'm not sure...some kind of straight line?
 
Check the meaning of the word "slope". It is a number not "some kind of line". What does the slope of a line mean?
 
ok i looked up slope and now know it is a number but the answer to this question still eludes me!

i don't know how you'd put the equation on a graph

the notes i have for this involve looking at the independence of say, x of the equation so I am rather stumped. also i just suck at graphs...
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top