How do I solve nodal analysis with a 2Ix voltage source at the red node?

[influx]

How do I find the voltage at the node with the red dot using nodal analysis? The 2I_x voltage source to the left of the node with the red dot makes it confusing for me...

Thanks

 

[gfd43tg]

First, I think you should find Ix in terms of the voltage at the red dot. Once you have Ix in terms of the node voltage, then you can use nodal analysis to find its value

 

[FOIWATER]

Do you have to use nodal that's sort of odd. Since the terminals are open, no current flows through the 5 ohm resistor and this is a simple series circuit

 

[influx]

Do you have to use nodal that's sort of odd. Since the terminals are open, no current flows through the 5 ohm resistor and this is a simple series circuit

Well my book uses mesh analysis. I was just wondering whether it is possible to use nodal analysis?

 

[influx]

First, I think you should find Ix in terms of the voltage at the red dot. Once you have Ix in terms of the node voltage, then you can use nodal analysis to find its value

The voltage at the red dot is 2I_x no?

 

[NascentOxygen]

The voltage at the red dot is 2I_x no?

No. That's the voltage of just one of the sources in a branch between Red Point and ground.

If you consider the other (shorter) branch between Red Point and ground, what is that branch voltage?

 

[influx]

No. That's the voltage of just one of the sources in a branch between Red Point and ground.

If you consider the other (shorter) branch between Red Point and ground, what is that branch voltage?

Is this correct?

 

[Jony130]

Yes, you got that part right.

 

[influx]

Yes, you got that part right.

Ok, so how would I apply nodal analysis now? I mean I can get (v-10)/3 but that's as far as I can get. I don't know how to treat the part to the right of node V.

 

[Jony130]

Treat it as one big node a supernode.

Whats comes in must come out.
(10 - V)/3Ω = ((V+ 2*Ix) - 0)/6Ω
And
Ix = (10 - V)/3Ω

 

[influx]

Treat it as one big node a supernode.

Whats comes in must come out.
(10 - V)/3Ω = ((V+ 2*Ix) - 0)/6Ω
And
Ix = (10 - V)/3Ω

The part in bold is the voltage that comes out of the red node rather than the blue node?

Thanks

 

[Jony130]

The part in bold is the voltage that comes out of the red node rather than the blue node?

Thanks

The part in the bold is a current that comes out of the red node. Or the current that leaves the positive terminal of a CCVS.