Engineering How do I solve this circuit using the impedance form?

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The discussion focuses on solving a circuit problem involving mutual inductance using impedance form. The original poster is struggling with methods involving energy equations and Kirchhoff's Voltage Law (KVL) for coils. A key suggestion is to treat mutual inductance as a current-controlled dependent voltage source in series with each loop's inductor. Participants confirm that instead of using differential equations, the problem can be approached using impedance directly, leading to two equations with two unknown currents. This method simplifies the analysis and allows for straightforward application of KVL.
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I am currently revising over some past papers and this question has come up which I am having problems with. My notes don't show how to solve this and I don't have any worked examples.

So far from looking on the internet, I have seen two methods. The first is using an equation for energy and the second is to use KVL for each coil and then substituting the equations.

I've tried to understand using both of these methods but I still can't apply to this question.

http://img714.imageshack.us/img714/3693/elecprob.jpg

Uploaded with ImageShack.us

If anyone could give me pointers on what I need to be doing, or a brief example of how it's done, it would be greatly appreciated as I'm having a hard time getting my head around it.

Thanks.
 
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How might you adjust the circuit diagram to incorporate the effects of the mutual inductance (the j3Ω indicated above the inductors) into each loop?
 
Would that be to convert it into a T-Circuit?
 
berryberry said:
Would that be to convert it into a T-Circuit?

Nope. The mutual inductance acts in each loop as though it were a current-controlled dependent voltage source in series with that loops inductor, with the control currents being the currents in the other loop.

For example, if M is the mutual inductance, i1 the current in the first loop, and i2 the current in the second loop, then in the first loop you could insert a voltage source in series with the inductor with a value M*i2. The same can be done for the second loop with the control current being i1.

This manipulation of the circuit diagram should allow you to write the KVL loop equations for each loop in a straightforward fashion.
 
If I'm understanding you correctly, that it is to use these equations (with the inclusion of R*I for the resistors)...
http://img189.imageshack.us/img189/750/unled1dg.jpg

Uploaded with ImageShack.us

If so what I have done so far is...

100/_0 = 10I1 + j10 dI1/dt + j3 dI2/dt
50/_45 = 5I2 +j5 dI2/dt + j3 dI1/dt

Although I'm not quite sure on how I would rearrange this, if this is the corrent way forward.
 
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berryberry said:
If I'm understanding you correctly, that it is to use these equations (with the inclusion of R*I for the resistors)...
http://img189.imageshack.us/img189/750/unled1dg.jpg

Uploaded with ImageShack.us

If so what I have done so far is...

100/_0 = 10I1 + j10 dI1/dt + j3 dI2/dt
50/_45 = 5I2 +j5 dI2/dt + j3 dI1/dt

Although I'm not quite sure on how I would rearrange this, if this is the corrent way forward.

Yes, you're on the right track. Since you're dealing with sinusoidal sources of the same frequency and you're given the impedances of the reactive components (the inductances), you can dispense with the differential form and use the impedances directly.

You'll have two equations in two unknowns (the currents).
 
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gneill said:
(the inductances), you can dispense with the differential form and use the impedances directly.

I'm not sure what you mean by this.

I assume replacing di/dt for just I?
 
berryberry said:
I'm not sure what you mean by this.

I assume replacing di/dt for just I?

Yup.
 
Impedance form: V=I*Z where Z=j*omega*M
 

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