Find Angle (theta) Given Displacement & Aircraft Velocity

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To find the angle (theta) of a dive bomber releasing a bomb from an altitude of 2.15 km with a displacement of 3.45 km, one must consider the time it takes for the bomb to hit the ground. Although the aircraft's velocity is not purely horizontal, the time can still be calculated using the vertical drop under gravity. The discussion highlights confusion regarding the relationship between the aircraft's angle and the time of descent. Ultimately, the participants emphasize that the angle can indeed be determined through proper calculations. The conversation reflects the complexities involved in solving projectile motion problems in aviation contexts.
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A dive bomber has a velocity of 275 m/s at an angle (theta) below the horizontal. When the altitude of the aircraft is 2.15 km, it releases a bomb, which subsequently hits a target on the ground. The magnitude of the displacement from the point of release of the bomb to the target is 3.45 km. Find the angle (theta).

OK, I'm not seeing a way to solve this without being given the time (t) it took for it to hit the ground, am i missing something here?
 
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You know the time. If it is released from 2.15 km, and it is subject to g, simply figure out how long it takes to reach the ground. Ignore the horizontal portion for now.
 
civil_dude said:
You know the time. If it is released from 2.15 km, and it is subject to g, simply figure out how long it takes to reach the ground. Ignore the horizontal portion for now.

but the plane's velocity isn't horizontal...therefore, the time to reach the ground can't be solved...
 
i asked my teacher about this today, he couldn't figure it out either...
 
2.3 degrees or 78 degrees?
like civil said,it can be calculated..just check again.
 
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